y=sin(ln(2x^2-5x))

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Solution for y=sin(ln(2x^2-5x)) equation: 


Simplifying
y = sin(ln(2x2 + -5x))

Reorder the terms:
y = ins(ln(-5x + 2x2))
y = ins((-5x * ln + 2x2 * ln))
y = ins((-5lnx + 2lnx2))
y = (-5lnx * ins + 2lnx2 * ins)
y = (-5iln2sx + 2iln2sx2)

Solving
y = -5iln2sx + 2iln2sx2

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Simplifying
y = -5iln2sx + 2iln2sx2

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